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(-3x^2)+4x+74=0
We get rid of parentheses
-3x^2+4x+74=0
a = -3; b = 4; c = +74;
Δ = b2-4ac
Δ = 42-4·(-3)·74
Δ = 904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{904}=\sqrt{4*226}=\sqrt{4}*\sqrt{226}=2\sqrt{226}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{226}}{2*-3}=\frac{-4-2\sqrt{226}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{226}}{2*-3}=\frac{-4+2\sqrt{226}}{-6} $
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